Simone求解数学题目详细解题过程…
的有关信息介绍如下：
只能算是提供点思路，太难解了！原式换成；ctga=(600+200√3+m)/n,ctg2a=(200√3+m)/n, ctg4a=m/n因为ctg2a=(ctga -1/ctga) /2ctg4a=(ctg2a-tg2a)/2=(ctga-tga)/4 - (ctga-tga)为表达清楚，令ctga=x, tga=1/x则 ctga= x =(600+200√3+m)/n (1)ctg2a=(x-1/x)/2= (200√3+m)/n (2) ctg4a=(x-1/x)/4 - x/(x^2 -1) = m/n (3)(1)减(2)得 x/2 + 1/2x = 600/n (4)(2)减(3)得 x/4 - 1/4x + x/(x^2-1) = 200√3 / n (5)(5)除以(4)得[x/4 - 1/4x + x/(x^2-1) ] / (x/2 + 1/2x) = √3 / 3解得 x = ctga =
